Krishna Geetha - Study24x7
Social learning Network
Krishna Geetha Cover image
Krishna Geetha
Krishna Geetha
Connections 0
Followers 0
Following 0
study24x7Krishna Geetha

Krishna Geetha

Live in India,
  • Profile
  • About
  • Connections
About
No user info
Krishna Geetha
29 Aug 2024 08:47 PM study24x7 study24x7

ABCD is a trapezium.AB||CD,E&F are midpoint an AD and BC . If AB=10cm,CD=6cm,then EF is

Class 8 IIT-JEE
Like | 1 Comment | 1 Share
study24x7
Write a comment
  • Dev kumar
    • The length of the midsegment EF in a trapezium can be calculated using the formula: EF = AB + CD/2 Given: AB=10 cm CD=6 cm Now, applying the formula: EF = 10 + 6 / 2 = 8 cm So, the length of 𝐸𝐹 is 8 cm.

    See more

    Like
    Reply 30 Aug 2024 10:17 AM
    Connections

    No connection