There  is a three  digit  number, N=xyz; where  x,y,z are different  digit. If x^2 y^2=41,x^2 z^2=89 andy^2 z^2=80,find N= ? - Study24x7
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Kashi Jha
29 May 2020 06:12 PM study24x7 study24x7

There  is a three  digit  number, N=xyz; where  x,y,z are different  digit. If x^2 +y^2=41,x^2+z^2=89 andy^2+z^2=80,find N= ?

A

458

B

854

C

548

D

485

Class 8 Class 9 Class 10
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