ABCD is a trapezium.AB||CD,E&F are midpoint an AD and BC . If AB=10cm,CD=6cm,then EF is - Study24x7
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Krishna Geetha
29 Aug 2024 08:47 PM study24x7 study24x7

ABCD is a trapezium.AB||CD,E&F are midpoint an AD and BC . If AB=10cm,CD=6cm,then EF is

Class 8 IIT-JEE
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  • Dev kumar
    • The length of the midsegment EF in a trapezium can be calculated using the formula: EF = AB + CD/2 Given: AB=10 cm CD=6 cm Now, applying the formula: EF = 10 + 6 / 2 = 8 cm So, the length of 𝐸𝐹 is 8 cm.

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    Reply 30 Aug 2024 10:17 AM
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